A body "A" of weight 10 kg with its center of gravity 25 cm from the axis of rotation is to be balanced by another body ‘B’ of weight 5 kg. The radius at which the center of gravity of weight ‘B’ should be placed is

A body "A" of weight 10 kg with its center of gravity 25 cm from the axis of rotation is to be balanced by another body ‘B’ of weight 5 kg. The radius at which the center of gravity of weight ‘B’ should be placed is Correct Answer 50 cm

Concept:

For the balancing of the two bodies, 

the centrifugal force should be same, i.e. F1 = F2

⇒ (mrω2)1 = (mrω2)2

The speed of both bodies is same,

Therefore, (mr)1 = (mr)2

Calculation:

Given:

m1 = 10 kg, r1 = 25 cm, m2 = 5 kg

⇒ 10 × 25 = 5 × r2

⇒ r2 = 50 cm

Related Questions

According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $$I$$P) is given by (where, A = Area of the section, $$I$$G = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $${I_{\text{P}}}$$) is given by (where, A = Area of the section, $${I_{\text{G}}}$$ = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)