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A conductor carries a current of 8A and if magnitude of charge of an electron e = 1.6 × 10-19 coulomb, then the number of electrons which flow through the cross section per second is -

A conductor carries a current of 8A and if magnitude of charge of an electron e = 1.6 × 10-19 coulomb, then the number of electrons which flow through the cross section per second is - Correct Answer <span style="">5.0 </span><span style="">× 10</span><span style=" line-height: 0; position: relative; vertical-align: baseline; top: -0.5em; font-size:10.5px;">19</span>

Concept:

Current passing through the conductor, I = q/t = ne / t

Where

n = number of electrons 

e = charge of electron

t = time duration

Calculation:

q = e = 1.62 × 10-19 

t = 1 sec

⇒ I = n × 1.62 × 10-19

⇒ 8 = n × 1.62 × 10-19

⇒ n = 4.93 × 1019 ≈ 5 × 1019

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