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In ∆ABC, a line parallel to side BC cuts the side AB and AC at points D and E respectively and also point D divide AB in the ratio of 1 : 4. If area of ∆ABC is 200 cm2 ,what is the area of quadrilateral DECB?

In ∆ABC, a line parallel to side BC cuts the side AB and AC at points D and E respectively and also point D divide AB in the ratio of 1 : 4. If area of ∆ABC is 200 cm2 ,what is the area of quadrilateral DECB? Correct Answer 192

Area of triangle ∆ADE = Area of ∆ABC × (AD/AB)2 = 200/25 = 8 cm2

Area of quadrilateral DECB = Area of ∆ABC - ∆ADE = 200 - 8 = 192 cm2

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