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One test tube contains some chemical and another test tube contains an equal quantity of water. To prepare a solution, 20 g of the chemical is poured into the second test tube. Then, two-thirds of the formed solution is poured from the second test tube into the first. If the fluid in the first test tube is four times that in second, what quantity of water was taken initially.

One test tube contains some chemical and another test tube contains an equal quantity of water. To prepare a solution, 20 g of the chemical is poured into the second test tube. Then, two-thirds of the formed solution is poured from the second test tube into the first. If the fluid in the first test tube is four times that in second, what quantity of water was taken initially. Correct Answer 40 g

Let y g of water and chemical was taken.

Initially 1st process

First test tube = (y – 20) g

Second test tube = (y + 20) g

2nd process

First test tube = (y – 20) + (y + 20) × (2/3)

Second test tube = (y + 20) × (1/3)

Now,

(y -20) + (2/3)(y +20) = 4 × (1/3)(y + 20)

On solving, y= 40 g

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