Pandey can do as much work in 4 days as Mishra can do in 6 days, and Mishra can do as much work in 5 days as Tiwari in 8 days. In what costing do Tiwari do a piece of work which Pandey can do in 70 days, if Tiwari gets Rs. 1 for 1 day?
Pandey can do as much work in 4 days as Mishra can do in 6 days, and Mishra can do as much work in 5 days as Tiwari in 8 days. In what costing do Tiwari do a piece of work which Pandey can do in 70 days, if Tiwari gets Rs. 1 for 1 day? Correct Answer Rs. 168
Let, Pandey, Mishra and Tiwari as P, Q and R respectively.
P × 4 = Q × 6
⇒ P/Q = 3/2
⇒ P ∶ Q = 3 ∶ 2
Q × 5 = R × 8
⇒ Q/R = 8/5
⇒ Q ∶ R = 8 ∶ 5
| P | Q | R |
| 3 × 4 = 12 | 2 × 4 = 8 | |
| 8 × 1 = 8 | 5 × 1 = 5 |
P : Q : R = 12 : 8 : 5
Let R do the work in x days which P can do in 70 days.
Then, P × 70 = R × x
⇒ 12 × 70 = 5 × x
⇒ x = 168 days
Now, Cost of R for 1 day = Rs. 1
Cost of R for 168 days = Rs. 168
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Feb 20, 2025