Pandey can do as much work in 4 days as Mishra can do in 6 days, and Mishra can do as much work in 5 days as Tiwari in 8 days. In what costing do Tiwari do a piece of work which Pandey can do in 70 days, if Tiwari gets Rs. 1 for 1 day?

Pandey can do as much work in 4 days as Mishra can do in 6 days, and Mishra can do as much work in 5 days as Tiwari in 8 days. In what costing do Tiwari do a piece of work which Pandey can do in 70 days, if Tiwari gets Rs. 1 for 1 day? Correct Answer Rs. 168

Let, Pandey, Mishra and Tiwari as P, Q and R respectively.

P × 4 = Q × 6

⇒ P/Q = 3/2

⇒ P ∶ Q = 3 ∶ 2 

Q × 5 = R × 8

⇒ Q/R = 8/5

⇒ Q ∶ R = 8 ∶ 5 

P R
3 × 4 = 12 2 × 4 = 8  
  8 × 1 = 8 5 × 1 = 5

P : Q : R = 12 : 8 : 5

Let R do the work in x days which P can do in 70 days.

Then, P × 70 = R × x

⇒ 12 × 70 = 5 × x

⇒ x = 168 days

Now, Cost of R for 1 day = Rs. 1

Cost of R for 168 days = Rs. 168

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