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An alloy contains tin and copper in the ratio 4 : 5. If tin has 20% impurity and copper 58%, what is the average % impurity?

An alloy contains tin and copper in the ratio 4 : 5. If tin has 20% impurity and copper 58%, what is the average % impurity? Correct Answer 41.1%

Ratio of alloy contains tin and copper = 4 : 5 or = 400x : 500x

Total quantity of impurity in tin = 400x × (20/100) = 80x

Total quantity of impurity in copper = 500x × (58/100) = 290x

Total quantity of impurity = 80x + 290x = 370x

Required percentage = (370x/900x) × 100 = 41.1%

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