Two positive numbers A and B are equidistant from 56 and HCF and LCM of A and B is 16 and 192 respectively, then what can be the difference between LCM and HCF of A and 56?
Two positive numbers A and B are equidistant from 56 and HCF and LCM of A and B is 16 and 192 respectively, then what can be the difference between LCM and HCF of A and 56? Correct Answer 440
Given:
HCF = 16
LCM = 192
Formula Used:
First number × Second number = HCF × LCM
Calculation:
Let A and B be at ‘x’ distance from 56.
⇒ A = (56 + x) or (56 – x)
⇒ B = (56 – x) or (56 + x)
Now,
(56 + x) × (56 – x) = 16 × 192
⇒ 3136 – x2 = 3072
⇒ x2 = 64
⇒ x = 8
A = 64 or 48
⇒ LCM of A and 56 when A is 64 = 448
⇒ HCF of A and 56 when A is 64 = 8
Required difference = 440
⇒ LCM of A and 56 when A is 48 = 336
⇒ HCF of A and 56 when A is 48 = 8
Required difference = 336 – 8 = 328
∴ The required difference is either 440 or 328.
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Feb 20, 2025