Two positive numbers A and B are equidistant from 56 and HCF and LCM of A and B is 16 and 192 respectively, then what can be the difference between LCM and HCF of A and 56?

Two positive numbers A and B are equidistant from 56 and HCF and LCM of A and B is 16 and 192 respectively, then what can be the difference between LCM and HCF of A and 56? Correct Answer 440

Given:

HCF = 16

LCM = 192

Formula Used:

First number × Second number = HCF × LCM

Calculation:

Let A and B be at ‘x’ distance from 56.

⇒ A = (56 + x) or (56 – x)

⇒ B = (56 – x) or (56 + x)

Now,

 (56 + x) × (56 – x) = 16 × 192

⇒ 3136 – x2 = 3072

⇒ x2 = 64

⇒ x = 8

A = 64 or 48

⇒ LCM of A and 56 when A is 64 = 448

⇒ HCF of A and 56 when A is 64 = 8

Required difference = 440

⇒ LCM of A and 56 when A is 48 = 336

⇒ HCF of A and 56 when A is 48 = 8

Required difference = 336 – 8 = 328

∴ The required difference is either 440 or 328. 

Related Questions