A labor is trying to pull a block of mass m on an inclined frictionless plane using a system of. What will be the magnitude of minimum force needed to pull this block up (consider rope and pulley are massless)?

A labor is trying to pull a block of mass m on an inclined frictionless plane using a system of. What will be the magnitude of minimum force needed to pull this block up (consider rope and pulley are massless)? Correct Answer mg sin θ

Concept:

  • Force: It is a kind of push or pulls applied to an object which causes it to accelerate at a certain rate
  • i.e., Force produces acceleration in a body.

∴ F = m × a

  • A simple machine that uses wheel and rope to lift a heavy load is called a pulley system
  • Pulley: It is a simple wooden or metallic machine that uses the wheel and rope to lift heavy loads.
  • Tension: The tension force is defined as the force that is transmitted through a rope, string, or wire when pulled by forces acting from opposite sides.
  • Mass: It is the measure of the amount of matter in a body. The SI unit of mass is kilogram (kg)
  • Weight: It is the measure of the force of gravity acting on a body.

And the weight of the body is given as,

Weight of body (W) = mass (m)× acceleration due to gravity (g)

Here,

Mass of object/body = m

Rate of acceleration = a

Acceleration due to gravity = g

Force acting on object = F

Explanation:

According to our given condition,

If a block of mass m is kept on an inclined plane its free body diagram can be represented as

[ alt="F1 J.S Madhu 02.06.20 D3" src="//storage.googleapis.com/tb-img/production/20/06/F1_J.S_Madhu_02.06.20_D3.png" style="width: 289px; height: 188px;">

Here g is acceleration due to gravity acting on the block whereas g cos θ and g sin θ is its cos and sin component respectively.

From this we can see that the block will be accelerated downward at the rate of g sinθ .

Thus, the net force needed to pull the block upward must be greater than or equal to mg sin θ

i.e., Fmin = mg sin θ 

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