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In a recent survey, 60% of houses contain two or more people, and the rest of the houses contain only one person. In houses containing only one person, 35% were having only a male. What is the percentage of all houses which contained exactly one female and no males?

In a recent survey, 60% of houses contain two or more people, and the rest of the houses contain only one person. In houses containing only one person, 35% were having only a male. What is the percentage of all houses which contained exactly one female and no males? Correct Answer <p>26%</p>

Formula:

If a = x% of b

⇒ a = (x/100) × b

Solution:

Let the total population be 100

Number of houses having only 1 person = 40/100 × 100 = 40

Number of houses having 1 female and no male = 65/100 × 40 = 26

∴ Required percent = (26/100) × 100 = 26%

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