Given,
φ= 3
P = 12Kw P. f = 0.6 lead
VL=208V
IL =?, Zp =?
cos θ = 0.6
θ=∠-35.13° (Lead)
Soln :
P=3 VLILcos θ
12=3 ×0.208 ×IL×0.6
At star connection IL=Ip=55.51Amp
VP=VL3=2083=120V
Zp=VpIp=12055.51 =2.16 Amp
Zp=2.16 ∠-35.13° (Ans)
You need to log in to continue.
You need to download the app to make a call.