We know, f'=10 logI1I0⇒85=10 logI1I0
⇒logI1I0=8.5⇒I1I0=108.5 ⇒I1=108.5I0
অনুরূপভাবে, I2=107.8I0 ∴I=I1+I2=108.5+107.8I0
∴β=10 logII0=10 log108.5+107.8=85.79 dB Ans.
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