Rafiq, Shafiq and Arif can alone complete a project in 10 days , 20 days, and 10 days respectively , Rafiq started working on the project alone, Shafiq the project after 2 days, after working together for 4 days both Rafiq and Shafiq left the project and Arif git in. How many days it took to complete the entire project? (work & time)

Shohan

14 views

2025-01-04 04:42

1 Answers

Shohan

Rafiq can do in 1 day= $\frac{1}{10}$ portion of work

Rafiq can do in 6 days = $\frac{6}{10} = \frac{3}{5}$ portion of work

Shafiq can do in 1 day= $\frac{1}{20}$ portion of work

Shafiq can do in 4 days = $\frac{4}{20} = \frac{1}{5}$ portion of work

Rafiq & Shafiq completed in first 6 days= $\frac{3}{5} + \frac{1}{5} = \frac{4}{5}$ portion of work

So, the remaining work = $(1 - \frac{4}{5}) = \frac{1}{5}$ portion of work

Arif can do in 1 day = $\frac{1}{10}$ portion of work

Arif can do $\frac{1}{10}$ portion in 1 day

Arif can do $\frac{1}{5}$ portion in = $\frac{10}{5} = 2$ days

The required time for completion of the work=6+2=8 days ans.

14 views Answered 2024-12-14 13:31

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