PCl5→←PCl3+Cl2 (0.1) 0 0 (0.1-α) α α
অতএব, n=0.1-α+α+α=(0.1+α)
আমরা জানি, PV=nRT⇒n=4.38×105×1×10-38.314×450=0.11707 mol
শর্তমতে, 0.1+α=0.11707⇒α=0.01707
অতএব, Kp=PPCl3.PCL2PPCl5=α0.1+αα0.1+α×P2total 0.1-α0.1+α×Ptotal =α20.1+α×Ptotal0.1-α
= 13145.70Nm-2 = 0.129738 atm
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