Length of each equal side of an isosceles triangle is 10cm and the included angle between those two sides is 45°. Find the area of the triangle. (Geometry (Triangle))

Shohan

7 views

2025-01-04 04:42

1 Answers

Shohan

Let, x be the perpendicular drawn from the vertex of the triangle

We know,

$\sin 45 ° = \frac{P e r p e n d i c u l a r}{H y p o t e n u s e} \Rightarrow \frac{1}{\sqrt{2}} = \frac{x}{10} ∴ x = \frac{10}{\sqrt{2}}$

Now, we know area of triangle

$= \frac{1}{2} \times b a s e \times h e i g h t = \frac{1}{2} \times 10 \times \frac{10}{\sqrt{2}} = \frac{50}{\sqrt{2}} = \frac{25 \times \sqrt{2} \times \sqrt{2}}{\sqrt{2}} = 25 \sqrt{2}$ ans.

7 views Answered 2024-12-14 13:31

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