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1 Answers

From given data,

$sint=0.8$ & $cos t=0.6$

Let $x=sint+cos(-t)+sin(2pi-t)$

[$cos(-t)=cost & sin(2pi-t)=-sint$]

$:.x=sint+cost-sint$

$=>x=cancelsint+cost-cancelsint$

$=>x=cost$

$:.x=0.6$

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