The rate of formation of `SO_(3)` in the reaction
`2SO_(2)+O_(2) rarr 2SO_(3)`
is 100 g `"min"^(-1)` Hence rate of disappearance of `O_(2)` is
A. 29 g `"min"^(-1)`
B. 20 g `"min"^(-1)`
C. 50 g `"min"^(-1)`
D. 200 g `"min"^(-1)`

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1 Answers

Correct Answer - B
`2SO_(2)+O_(2)rarr2SO_(3)`
Rate `=-(d[O_(2)])/(dt)=(1)/(2)(d[SO_(3)])/(dt)`
`-(d[O_(2)])/(dt)=(1)/(2)((100)/(80))" mol min"^(-1)=(1)/(2)((100)/(80))xx32 g " min"^(-1)`
`[because" Molar mass of "O_(2)=32 g//"mol"]`
`=20g " min"^(-1)`

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