If `S(g)+e^(-) rarr S^(1-)(g), Delta H = -207.6 KJ`
`S(g) + 2e^(-) rarr S^(2-)(g), Delta H = +335.2 KJ`.
The enthalpy for the reaction
`S^(1-)(g)+e^(-) rarr S^(2-)(g)`:
A. `+127.6 KJ`
B. `-127.6 KJ`
C. `+542.8 KJ`
D. `-641.8 KJ`

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1 Answers

Correct Answer - C
`Delta H = H_(P-H_(R))`

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