A ball is thrown vertically upwards with a speed of `10 m//s` from the top of a tower 200 m height and another is thrown vertically downwards with the same speed simultaneously. The time difference between them on reaching the ground is `(g=10 m//s^(2))`
A. 12 s
B. 6 s
C. 2 s
D. 1 s

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1 Answers

Correct Answer - C
`Deltat=(2u)/(g)`

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