1. The heights of 15 boys of a shoot are given \( cm \) : \( 148,128,146,143,152,139,140,142,149,154,132,157,165,139,142 \) Arrange the above data in an ascending order and find: a. The height of the tallest boy. b. The height of the shortest boy. c. The mean height.

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Ascending order of heights of 15 boys is :

128,132,139,140,142,143,146,148,149,152,154,157,165

The height of tallest boy = 165 cm

The height of smallest boy = 128 cm

The mean height = \(\frac{\Sigma x_i}{n}\)

= \(\frac{2176}{15}\) 

= 145.067 ≈ 145 cm

Given : The heights of 15 boys in ascending order :

             128, 132, 139, 139, 140, 142, 142, 143, 146, 148, 149, 152, 154, 157, 165.

a. The height of the tallest boy is 165 cm.

b. The height of the shortest boy is 128 cm.

c. The mean height = \((\sum x_i )/ n\)

                                = (128 + 132 + 139 + 139 + 140 + 142 + 142 + 143 + 146 + 148 + 149 + 152 + 154 + 157 + 165) / 15

                                = 2176 / 15

                                = 145.067

                                \(\approx\) 145 cm.