1. The heights of 15 boys of a shoot are given \( cm \) : \( 148,128,146,143,152,139,140,142,149,154,132,157,165,139,142 \) Arrange the above data in an ascending order and find: a. The height of the tallest boy. b. The height of the shortest boy. c. The mean height.
1. The heights of 15 boys of a shoot are given \( cm \) : \( 148,128,146,143,152,139,140,142,149,154,132,157,165,139,142 \) Arrange the above data in an ascending order and find: a. The height of the tallest boy. b. The height of the shortest boy. c. The mean height.
3 Answers
Ascending order of heights of 15 boys is :
128,132,139,140,142,143,146,148,149,152,154,157,165
The height of tallest boy = 165 cm
The height of smallest boy = 128 cm
The mean height = \(\frac{\Sigma x_i}{n}\)
= \(\frac{2176}{15}\)
= 145.067 ≈ 145 cm
Given : The heights of 15 boys in ascending order :
128, 132, 139, 139, 140, 142, 142, 143, 146, 148, 149, 152, 154, 157, 165.
a. The height of the tallest boy is 165 cm.
b. The height of the shortest boy is 128 cm.
c. The mean height = \((\sum x_i )/ n\)
= (128 + 132 + 139 + 139 + 140 + 142 + 142 + 143 + 146 + 148 + 149 + 152 + 154 + 157 + 165) / 15
= 2176 / 15
= 145.067
\(\approx\) 145 cm.