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For the given AP the first term a is 1, and common difference d is a difference of the second term and first term, which is 2 - 1 = 1
To find : the sum of given AP
The formula for the sum of AP is given by,
s = \(\frac{n}{2}\)(2a+(n-1)d)
Substituting the values in the above formula,
s = \(\frac{n}{2}\)(2+(n-1)(1))
s = \(\frac{n(n+1)}{2}\)
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