The sum of three numbers is 2. If twice the second number is added to the sum of first and third, we get 1. On adding the sum of second and third numbers to five times the first, we get 6. Find the three numbers by using matrices.
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There are three odd numbers and one even number. What type of number is their sum ?
Correct option is (D) Odd number Sum of three odd numbers is odd. Sum of an odd number and an even number is odd. \(\therefore\) Sum of three odd numbers and one even number is odd.
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There are three odd numbers and one even number. What type of number is their sum ?
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‘The difference between a number and twice the second number is 14’ in linear form
Correct option is (D) x – 2y – 14 = 0 Let first number is x and second number is y. \(\therefore\) x - 2y = 14 (According to given condition) \(\Rightarrow\) x –...
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‘The difference between a number and twice the second number is 14’ in linear form
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Means of first 10 whole numbers and first 10 natural numbers is in the ratio of
Correct option is (A) 9: 11 Mean of first 10 whole numbers \(=\frac{0+1+2+....+9}{10}\) \(=\frac{9\times10}{20}=\frac92\) Mean of first 10 natural numbers \(=\frac{1+2+3+....+10}{10}\) \(=\frac{10\times11}{20}=\frac{11}2\) \(\therefore\) Their ratio \(=\cfrac{\frac92}{\frac{11}2}\) \(=\frac9{11}\) = 9 : 11
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In a senior secondary school,80 students play football or hockey.The number that play football is 5 more than twice the number that play hockey.If 15 students play both games and every student in the school plays at least one game,find (i)the number of students that play football (ii)the number of students that play football but not hockey (iii)the number of students that play hockey but not football.
I thought F or H = 80 is giving by n(F u H) = n(F) + n(H) - n(F n H)
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The sum of two Rational numbers is 1/2 and one of the numbers is -8/19 then the second number is ………………
Correct option is (D) 35/38 Let the second number be x. \(\therefore\) x + \((\frac{-8}{19})\) = \(\frac{1}{2}\) \(\Rightarrow\) x = \(\frac{1}{2}\) - \((\frac{-8}{19})\) = \(\frac{1}{2}\) + \(\frac{8}{19}\) \(=\frac{19+8\times2}{38}\) \(=\frac{19+16}{38}\) \(=\frac{35}{38}.\)
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