If ω(≠1) is a cube root of unity and (1 + ω)^7 = A + Bω, then A and B are respectively the numbers (A) 0, 1 (B) 1, 1 (C) 1, 0 (D) -1, 1

If ω(≠1) is a cube root of unity and (1 + ω)⁷ = A + Bω, then A and B are respectively the numbers

(A) 0, 1

(B) 1, 1

(C) 1, 0

(D) -1, 1

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

(B) 1, 1

(1 + ω)⁷

= (-ω²)⁷

= -ω¹⁴

= -ω² (ω³)⁴

= -ω²

= 1 + ω

A = 1, B = 1

6 views Answered 2023-02-05 15:29

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