If ω is a complex cube root of unity, then the value of ω^99 + ω^100 + ω^101 is: (A) -1 (B) 1 (C) 0 (D) 3

If ω is a complex cube root of unity, then the value of ω⁹⁹ + ω¹⁰⁰ + ω¹⁰¹ is:

(A) -1

(B) 1

(C) 0

(D) 3

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

(C) 0

ω⁹⁹ + ω¹⁰⁰ + ω¹⁰¹

= ω⁹⁹ (1 + ω + ω²)

= ω⁹⁹(0)

= 0

5 views Answered 2023-02-05 15:29

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