In a deviation problem Σfi di = – 12 and A = 15; Σf = 20 then X =
In a deviation problem Σfi di = – 12 and A = 15; Σf = 20 then \(\overline{X}\)=
A) 15.6
B) 14.6
C) 14.4
D) 12.4
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Correct option is (C) 14.4
\(\bar x=A+\frac{\sum f_id_i}{\sum f_i}\)
\(=15-\frac{12}{20}\)
= 15 - 0.6
= 14.4
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