In ΔPQR, PQ = 5 cm, QR = 12 cm and PR = 13 cm, then PQR is
In ΔPQR, PQ = 5 cm, QR = 12 cm and PR = 13 cm, then PQR is
A) an acute angled triangle
B) a right angled triangle
C) an obtuse angled triangle
D) an equilateral triangle
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Correct option is (B) a right angled triangle
\(\because5^2+12^2\) = 25+144
= 169 \(=13^2\)
\(\therefore PQ^2+QR^2=PR^2\) which is a condition that \(\triangle PQR\) is a right angled triangle.
(By converse of Pythagoras theorem)
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