If in ∆PQR, PQ > QR then
If in ∆PQR, PQ > QR then
A) ∠R < ∠P
B) ∠P > ZQ
C) ∠R > ∠P
D) ∠P < ∠Q
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Correct option is (C) ∠R > ∠P
Angle opposite to longer side is greater.
\(\because\) PQ > QR in \(\triangle PQR\)
\(\therefore\) Angle opposite to \(\frac{side\,PQ}{in\,\triangle PQR}>\frac{\text{Angle opposite to side QR}}{in\,\triangle PQR}\)
\(\Rightarrow\) \(\angle R>\angle P\)
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