In free space, an EM wave of frequency 28 MHz travels along the X-direction. The amplitude of the electric field is E = 9.6 V/m

Question

In free space, an EM wave of frequency 28 MHz travels along the X-direction. The amplitude of the electric field is E = 9.6 V/m

In free space, an EM wave of frequency 28 MHz travels along the X-direction. The amplitude of the electric field is E = 9.6 V/m and its direction is along the Y-axis. What is amplitude and direction of magnetic field B?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Given: v = 28 MHz, E = 9.6 V/m,

c = 3 × 10⁸ m/s

To find:

i. Amplitude of magnetic field (B)

ii. Direction of B

Formula:

|B| = \(\frac{|E|}{c}\)

Calculation: From formula,

|B| = \(\frac{9.6}{3\times10^8}\) = 3.2 × 10^-8 T

Since that E is along Y-direction and the wave propagates along X-axis. The magnetic induction, B should be in a direction perpendicular to both X and Y axes, i.e., along the Z-direction.