Focal length of the objective of an astronomical telescope is 1 m. Under normal adjustment, length of the telescope is 1.05 m.
Focal length of the objective of an astronomical telescope is 1 m. Under normal adjustment, length of the telescope is 1.05 m. Calculate focal length of the eyepiece and magnifying power under normal adjustment.
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Given: f0 = 1 m, L = 1.05 m
To find:
i. Focal length of eyepiece (fe)
Magnifying power under normal adjustment (M)
Formula:
i. L = f0 + fe
ii. M = \(\frac{f_0}{f_e}\)
Calculation: From formula (i),
fe = L – f0 = 1.05 – 1 = 0.05 m
From formula (ii),
M = \(\frac{1}{0.05}\) = 20
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