Calculate the percentage composition of the elements in HNO3 (H = 1, N = 14, O = 16).

Atomic mass of H = 1, N = 14 and O = 16 

The mass percentage of H, N and O in HNO₃

Formula :

Percentage (by weight) = \(\frac{Mass\,of\,the\,element\,in\,1\,mole\,of\,compound}{Molar\,mass\,of\,the\,compound}\) x 100

Calculation : 

Molecular formula of HNO₃

∴ Molar mass = 1 × (1) + 1 × (14) + 3 × (16) 

= 1 + 14 + 48 

= 63 g mol^-1

∴ Percentage of H = \(\frac{1}{63}\) × 100 = 1.59%

Percentage of N = \(\frac{14}{63}\) × 100 = 22.22%

Percentage of O = \(\frac{48}{63}\) x 100 = 76.19%

∴ Mass percentage of H, N and O in HNO₃ are 1.59%, 22.22% and 76.19% respectively.

Percentage of Hydrogen = 1/63 x 100 = 1.58 %

Nitrogen = 14/63 x 100 = 22.2%

Oxygen = 48/63 x 100 = 76.19%