A sample of calcium carbonate (CaCO3) has the following percentage composition : Ca = 40 %; C = 12 %; O = 48 %.
A sample of calcium carbonate (CaCO3) has the following percentage composition :
Ca = 40 %; C = 12 %; O = 48 %. If the law of definite proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate from another source will be ……………..
(A) 0.016 g
(B) 0.16 g
(C) 1.6 g
(D) 16 g
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(C) 1.6 g
Law of constant proportional, state that "the individual elements that constitute a chemical compound are always present in a fixed ratio (by mass)". This ratio does not depend on the source of the chemical compound.
\(\therefore \) weight of calcium in 4g of sample = \(4\times\frac{40}{100}\)
= \(1.6\) g
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