A copper wire has a resistance of \( 0.60 hm \). Anozner copper wire of the samemass as the first one is dou ble in length of the first. Find the resistance of the second wire.
A copper wire has a resistance of \( 0.6 0hm \). Another copper wire of the same mass as the first one is double in length of the first. Find the resistance of the second wire.
9 views
1 Answers
We know that R = ρl/A
R ∝ l
R1/R2 = l1/l2
Given
∵ l2 = 2l1
R1 = 0.60 hm
R2/R1 = l2/l1
R2/R1 = 2l1/l1
R2 = 2 R1
R2 = 2 x 0.60
R2 = 1.2 hm
9 views
Answered