A ball is dropped from the top of a building 122.5 m high. How long will it take to reach the ground? What wilt be its velocity
A ball is dropped from the top of a building 122.5 m high. How long will it take to reach the ground? What wilt be its velocity when it strikes the ground?
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Given: s = h = 122.5 m, u = 0,
a = g = 9.8 ms2
To find: (i) Time taken to reach the ground (t)
(ii) Velocity of ball when it strikes ground (v)
Formulae: (i) s = ut + \(\frac{1}{2}\) at2
(ii) v = u + gt
Calculation: From formula (i),
122.5 = 0 + \(\frac{1}{2}\) × 9.8 t2
t2 = \(\frac{122.5}{4.9}\) = 25
t = \(\sqrt{25}\) = 5 second
From formula (ii),
v = u + gt
v = 0 + 9.8 × 5 = 49 m/s
(i) Time taken to reach the ground is 5 s.
(ii) Velocity of the ball when it strikes the ground is 49 m/s.
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