At a given temperature \( PbI _{2} \) will be more soluble in (a) \( 0.4 M Pb \left( NO _{3}\right)_{2} \) (b) \( 0.02 M Na 1 \) when (c) \( 0.02 MKI \) (d) water \( PbI _{2} \rightleftharpoons Pb ^{+} \)

Question

At a given temperature \( PbI _{2} \) will be more soluble in (a) \( 0.4 M Pb \left( NO _{3}\right)_{2} \) (b) \( 0.02 M Na 1 \) when (c) \( 0.02 MKI \) (d) water \( PbI _{2} \rightleftharpoons Pb ^{+} \)

Monjur Alahi

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2025-01-04 04:42

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

In water PbI₂ more soluble as compare to the given other solvents. In water there is no common ions effect while in, Pb(NO₃)₂, NaI and KI solvents, there are common ion effects due to this PbI₂ less soluble in these solvents compare to water.

5 views Answered 2023-02-05 15:29