The ionisation potential of mercury is 10.39 V. How far an electron must travel in an electric field of `1.5 xx 10^(6) V//m` to gain sufficient energy to ionise mercury ?
A. `(10.39)/(1.6xx10^(-19))` m
B. `(10.39)/(2xx1.6xx10^(-19))` m
C. `10.39 xx 1.6 xx 10^(-19)` m
D. `(10.39)/(1.5xx10^(6))` m

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1 Answers

E=dV/dx ......................................eq 1

here E=1.5 x \(10^6 \) V/m

dV=10.39 V

we have to find dx

so substituing in eq 1,we get

1.5 x\(10^6 \) = 10.39/dx

dx=10.39/1.5 x \(10^6\) m

so the answer is option d

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