Two, capacitors `A` and `B` are connected in series across a `100 V` supply and it is observed that the potential difference across them are `60 V` and `40 V`. A capacitor of `2 p.F` capacitance is now connected in parallel with `A` and the potential difference across B rises to `90 V`. Determine the capacitance of `A` and `B`

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Correct Answer - `0.16muF, 0.24 muF`

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