2cosA.cosB = (A) cos(A + B) + cos(A – B) (B) 2cosA.sinB

2cosA.cosB =

(A) cos(A + B) + cos(A – B)

(B) 2cosA.sinB

(C) cos(A – B) – cos(A + B)

(D) 2sinA.cosB

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct option is: (A) cos(A + B) + cos(A – B)

5 views Answered 2023-02-05 15:29

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