A square loop of mass m and side length a lies in xy plane with its centre at origin. It carries a current I. The loop is free to rotate about x axis. A magnetic field `vec(B)=B_(0 )= B_(0)vec(j)` is switched on in the region. Calculate the angular speed acquired by the loop when it has rotated through 90°. Assume no other force on the loop apart from the magnetic force.

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Correct Answer - `omega=sqrt((12IB_(0))/m`

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