1 Answers

let two no. be x1, x2 .
x1+ x2= 28..(1)
x1.x2= 192 ...(2)
by 1 and 2 put x1= 192/ x2 in eqn 1 and solve quadratic .x2^ 2 - 28x2+ 192 = 0 x2( x-16) - 12( x2 - 16) = 0(x2- 16)( x2- 12)= 0 x1 = 16 and x2 = 12



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