`y=x+2` is any tangent to the parabola `y^2=8xdot` The point `P` on this tangent is such that the other tangent from it which is perpendicular to it i

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`y=x+2` is any tangent to the parabola `y^2=8xdot` The point `P` on this tangent is such that the other tangent from it which is perpendicular to it i

`y=x+2` is any tangent to the parabola `y^2=8xdot` The point `P` on this tangent is such that the other tangent from it which is perpendicular to it is `(2,4)` (b) `(-2,0)` `(-1,1)` (d) `(2,0)`
A. (2,4)
B. (-2,0)
C. (-1,1)
D. (2,0)

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
(2) Clearly, P is the point of intersection of two perpendicular tangents to the parabola `y^(2)=8x`.
Hence, P must lie on the directrix x+a=0orx+2=0.
Therefore, x=-2.
Hence, the point is (-2,0).

6 views Answered 2023-02-05 15:29