Double ordinate `A B` of the parabola `y^2=4a x` subtends an angle `pi/2` at the focus of the parabola. Then the tangents drawn to the parabola at `Aa

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Double ordinate `A B` of the parabola `y^2=4a x` subtends an angle `pi/2` at the focus of the parabola. Then the tangents drawn to the parabola at `Aa

Double ordinate `A B` of the parabola `y^2=4a x` subtends an angle `pi/2` at the focus of the parabola. Then the tangents drawn to the parabola at `Aa n dB` will intersect at `(-4a ,0)` (b) `(-2a ,0)` `(-3a ,0)` (d) none of these
A. (-4a,0)
B. (-2a,0)
C. (-3a,0)
D. none of these

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
(1) Let `A-=(at^(2),2at),B-=(at^(2),-2at)`. Then
`m_(OA)=(2)/(t),m_(OB)=(-2)/(t)`
Thus, `((2)/(t))((-2)/(t))=-1`
`or" "t^(2)=4`
Thus, the tangents will intersect at (-4a,0).

6 views Answered 2023-02-05 15:29