The rate of a reaction depends upon the temperature and is quantitatively expressed as
`k=Ae^((-Ea)/(RT)`
i) If a graph is plotted between log k and 1/T, write the expression for the slope of the reaction?
ii) If at under different conditions `E_(a1)andE_(a2)` are the activation energy of two reactions. If `E_(a1) = 40 J// "mol and" E_(a2) = 80 J//" mol"`. Which of the two has a larger value of the rate constant?

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1 Answers

(i) `"Slope"=-(E_(a))/(2.303R)`
(ii) `k_(1)ltk_(2)`

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