Consider the following equilibrium `H_(2)O(g)+CO(g)hArrH_(2)(g)+CO_(2)(g),K_(1)=2` `FeO(s)+CO(g)hArrFe(s)+CO_(2)(g),K_(2)=4` Then K for reaction: `Fe(

Question

Consider the following equilibrium `H_(2)O(g)+CO(g)hArrH_(2)(g)+CO_(2)(g),K_(1)=2` `FeO(s)+CO(g)hArrFe(s)+CO_(2)(g),K_(2)=4` Then K for reaction: `Fe(

Consider the following equilibrium
`H_(2)O(g)+CO(g)hArrH_(2)(g)+CO_(2)(g),K_(1)=2`
`FeO(s)+CO(g)hArrFe(s)+CO_(2)(g),K_(2)=4`
Then K for reaction:
`Fe(s)+H_(2)O(g)hArrFeO(s)+H_(2)(g)`
A. 2
B. 1
C. `(1)/(3)`
D. `sqrt(2)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`H_(2)O(g)+CO(p)hArrH_(2)(g)+CO_(2)(g)`….(i)
`FeO(s)+CO(g)hArrFe(s)+CO_(2)(g)`…(ii)
Required reaction: `Fe(s)+H_(2)O(g)hArrFeO(s)+H_(2)(g)`…(iii)
Equation iii=Equation i-Equation ii
`K_(3)=(K_(1))/(K_(2))=(2)/(4)=(1)/(2)`

5 views Answered 2023-02-05 15:29