The average speed of nitrogen molecule is v. if the temperature is doubled and nitrogen molecule dissociate into nitrogen atoms completely then new average speed becoems.
A. v
B. `sqrt(2)v`
C. `2v`
D. 4v

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1 Answers

`v_(mg)=sqrt((8)/(pi)(RT)/(M))`
`N_(2)(g)rarr2N(g)`
`((v_(avg))N)/((v_(avg))N_(2))sqrt((28xx2T)/(14xxT))=sqrt(4)=2`
`(v_(avg))_(N)=2v`

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