The velocity function of an object moving along a straight line is given by `v(t)=At^(2)+Bt`. If at t=2s, the velocity is 3 m/s and acceleration is `0.500 m//s^(2)`, find the value of the constant A.
A. `-0.5m//s^(3)`
B. `-0.5 m//s^(2)`
C. `-2.5m//s^(3)`
D. `-1.5m//s^(2)`

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1 Answers

`v=At^(2)+BtrArr 3=4A+2B`
`a=2At+BrArr0.5=4A+B`
Now, solve for A

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