A light ray coming along the line `3x+4y=5` gets reflected from the line `a x+b y=1` and goes along the line `5x-12 y=10.` Then, `a=(64)/(115), b=(112
A light ray coming along the line `3x+4y=5`
gets reflected from the line `a x+b y=1`
and goes along the line `5x-12 y=10.`
Then,
`a=(64)/(115), b=(112)/(15)`
`a=(14)/(15), b=-8/(115)`
`a=(64)/(115), b=-8/(115)`
`a=(64)/(15), b=(14)/(15)`
A. `a=(64)/(115), b=(112)/(15)`
B. `a=(14)/(15), b=-(18)/(115)`
C. `a=(64)/(115), b=-(8)/(115)`
D. `a=(64)/(15), b=(14)/(15)`
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Correct Answer - C
ax+by=1 will be one of the bisectors of the given line.
Bisectors of the given lines are
`(3x+4y-5)/(5)=+-((5x-12y-10)/(13))`
`rArr 64x-8y=115 " or " 14x+112y=15`
`therefore a=(64)/(115),b=-(8)/(115) "or a =(14)/(15), b =(112)/(15)`
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