A particle falls from the top of a tower and it cover `(3)/(25)` of the total height from `t=2` sec to t=4 sec. The height of the tower is:-
A. 200m
B. 300m
C. 500m
D. 800m

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1 Answers

`h_(1)=5(2)^(2)=20`
`h_(2)=5(4)=80`
`h_(2)-h_(1)=60=(3)/(25)H`
H=500m

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