In a `triangle ABC` the sides `BC=5, CA=4` and `AB=3`. If `A(0,0)` and the internal bisector of angle A meets BC in D `(12/7,12/7)` then incenter of `

Question

In a `triangle ABC` the sides `BC=5, CA=4` and `AB=3`. If `A(0,0)` and the internal bisector of angle A meets BC in D `(12/7,12/7)` then incenter of `

In a `triangle ABC` the sides `BC=5, CA=4` and `AB=3`. If `A(0,0)` and the internal bisector of angle A meets BC in D `(12/7,12/7)` then incenter of `triangle ABC` is
A. `(2,2)`
B. `(3,2)`
C. `(2,3)`
D. `(1,1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
We have `a=5,b=4,c=3`
Incentre I divides AD int the ratio `b+c:a`.
Therefore,I divides AD in the ratio `7:5`
Hence, coordinates of I are (1,1).

4 views Answered 2023-02-05 15:29