A `10muF` capactor is connected withan ac source `E=200sqrt2 sin (100 t)V` through an ac ammeter (it reads rms value). What will be the reading of the

Question

A `10muF` capactor is connected withan ac source `E=200sqrt2 sin (100 t)V` through an ac ammeter (it reads rms value). What will be the reading of the

A `10muF` capactor is connected withan ac source `E=200sqrt2 sin (100 t)V` through an ac ammeter (it reads rms value). What will be the reading of the ammeter?

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

An inductor coil is connected to a 12V battery and drawing a current 24 A. This coil is connected to capacitor and an AC source of rms voltage rating

2 Answers 5 Views

At the top of a mountain a thermometer reads `7^(0)C` and barometer reads `70 cm` of `Hg`. At the bottom of the mountain the barometer reads `76 cm` o

2 Answers 5 Views

When a voltage `v_(S)=200sqrt2 sin (omega t+15^(@))` is applied to an `AC` circuit the current in the circuit is found to be `i=2 sin (omegat+pi//4)`

2 Answers 5 Views

Find the principal values of the following (i) `sin^(-1) (sin 1)` (ii) `sin^(-1) (sin 2)` (iii) `sin^(-1) (sin 10)` (iv) `sin^(-1) (sin 20)` (v) `sin^

2 Answers 5 Views

The value of `sin^(-1)[xsqrt(1-x)-sqrt(x)sqrt(1-x^2)]` is equal to `sin^(-1)x+sin^(-1)sqrt(x)` `sin^(-1)x-sin^(-1)sqrt(x)` `sin^(-1)sqrt(x)-sin^(-1)x`

2 Answers 5 Views

When a voltage `v_(s)=200sqrt2 sin (omega t=15^(@))` is applied to an AC circuit the current in the circuit is found to be `i=2som (omegat+pi//4)` the

2 Answers 5 Views

Prove that `^100 C_2^(100)C_2+^(100)C_2^(100)C_4+^(100)C_4^(100)C_6++^(100)C_(98)^(100)C_(100)=1/2[^(200)C_(98)-^(100)C_(49)]dot`

2 Answers 5 Views

In triangle ABC, `sinA sin B + sin B sin C + sin C sin A = 9//4 and a = 2`, then the value of `sqrt3 Delta`, where `Delta` is the area of triangle, is

2 Answers 5 Views

When an ideal voltmeter is connected between the points E and F (fig) the reading of the meter is `V_(0)`. When an ideal ammeter is connected between

2 Answers 5 Views

A steady current is passed for 25minutes through a silver voltameter and ammeter in series and 0.059g of silver of deposited. The ammeter reads 0.3A.

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`I_(0)=(V_(0))/(X_(C))=(200sqrt2)/(1//omegaC),I_("RMS")=(I_(0))/(sqrt2)=200mA`

5 views Answered 2023-02-05 15:29