In a triangle `A B C` , the bisectors of angles `Ba n dC` lies along the lines `x=ya n dy=0.` If `A` is `(1,2)` , then the equation of line `B C` is `

Question

In a triangle `A B C` , the bisectors of angles `Ba n dC` lies along the lines `x=ya n dy=0.` If `A` is `(1,2)` , then the equation of line `B C` is `

In a triangle `A B C` , the bisectors of angles `Ba n dC` lies along the lines `x=ya n dy=0.` If `A` is `(1,2)` , then the equation of line `B C` is `2x+y=1` (b) `3x-y=5` `x-2y=3` (d) `x+3y=1`
A. 2x+y=1
B. 3x-y=5
C. x-2y=3
D. x+3y=1

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
The reflections of A in the two angle bisectors will lie on the line BC, So, (2,1) and (1,-2) will lie on BC. The equation of BC will be
`y+2 = ((1+2)/(2-1))(x-1)`
i.e., 3x-y=5

4 views Answered 2023-02-05 15:29