The angle between the diagonals of a quadrilateral formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2` and `x/b+y/a=2` is (a) `pi/4` (b) `pi/6` (c) `p

Question

The angle between the diagonals of a quadrilateral formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2` and `x/b+y/a=2` is (a) `pi/4` (b) `pi/6` (c) `p

The angle between the diagonals of a quadrilateral formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2` and `x/b+y/a=2` is (a) `pi/4` (b) `pi/6` (c) `pi/3` (d) `pi/2`
A. `(pi)/(4)`
B. `(pi)/(2)`
C. `(pi)/(3)`
D. `(pi)/(6)`

Monjur Alahi

14 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Clearly, distance between the parallel lines `(x)/(a)+(y)/(b) = 1 " and " (x)/(a) + (y)/(b) = 2 " is same as the distance between the parallel lines "(x)/(b)+(y)/(a) = 1 " and " (x)/(b)+(y)/(b) = 2`.
Therefore, quadrilateral is rhombus.

14 views Answered 2023-02-05 15:29